How Do You Calculate the Second Displacement in Vector Problems?

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To calculate the second displacement in vector problems, first determine the x and y components of the first displacement, which has a magnitude of 167 cm at an angle of 161 degrees. The resultant displacement is 168 cm at 37.6 degrees, allowing for the calculation of its x and y components. By applying the equations for vector addition, the second displacement can be found by subtracting the first displacement's components from the resultant's components. The final magnitude of the second displacement is 294 cm, and its direction can be calculated using the inverse tangent function based on the resulting x and y components. Understanding these vector relationships is crucial for solving similar problems effectively.
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Help me please! sos

A man pushing a mop across a floor causes the mop to undergo two displacements. The first has a magnitude of 167cm and makes an angle 161 degrees with the positive x- axis. The resultant displacement has a magnitude of 168 cm and is directed at an angle of 37.6 degrees to the positive x- axis.

Find the magnitude of the second diplacement?
Find the direction of the second displacement with respect to the positive x-axis.( Consider counterclockwise to be positiveand answer within the limits of -180 degrees to180 degrees)
Now I have attempted this numerous times from many different views but have failed miserably. I enetered in as the online homework an got it wrong all 7 times only to find out that the answer is 294. Could someone please help me figure out how to solve this so that i may continue to the next problem, because it is a play on this one.
 
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What is the x-component and y-component of displacement 1?

What is the x-component and y-component of net displacement?

x-componnet of displacement 1 + x-component of displacement 2 = x-component of net displacement

y-componnet of displacement 1 + y-component of displacement 2 = y-component of net displacement
 

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