How Do You Calculate the Total Mass of a Cylinder with Variable Density?

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Homework Help Overview

The problem involves calculating the total mass of a solid cylinder defined by the inequality x^2 + y^2 ≤ 4, with specific bounds for z given by x^2 ≤ z ≤ 9 - x^2. The mass density is defined as p(x, y, z) = |y|. The context centers around variable density and integration over a three-dimensional volume.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to integrate the density function over the specified volume. Questions arise regarding the limits of integration, with one participant suggesting ranges for x and y, while others challenge these choices and propose alternative limits based on the geometric constraints of the cylinder.

Discussion Status

The discussion is active, with participants exploring different interpretations of the limits of integration and the setup of the problem. Some guidance has been offered regarding the correct boundaries for y and the use of polar coordinates, but no consensus has been reached on the approach to take.

Contextual Notes

Participants are grappling with the implications of the variable density and the geometric constraints imposed by the cylinder's equation. There is a noted confusion regarding the limits of integration, particularly for y, and the relationship between x and y within the context of the cylinder's shape.

TheSpaceGuy
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Total mass?

Homework Statement


Find the total mass of the part of the solid cylinder x^2 + y^2 ≤ 4 such that x^2 ≤ z ≤ 9 - x^2 , assuming that the mass density is p(x, y, z) = I y I (absolute value of y).


I have heard about center of mass but this is throwing me off?

The Attempt at a Solution



Thats where the problem is.
 
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All you have to do is integrate p(x,y,z) over the volume of interest.
 


But how would I get the limits of integration. How about choosing x from 0 to 4 and y is x^2 to 4? z is given. Am I on the right track?
 


Did you think about this very long? x can't 4 and satisfy [itex]x^2+ y^2= 4[/itex] for any y! And I have no idea how you got "y is x^2 to 4"! What do you get if you solve [itex]x^2+ y^2= 4[/itex] for y?

Perpendicular to the z-axis, the boundary is the cylinder [itex]x^2+ y^2= 4[/itex]. You could let x very from -2 to 2 and, then, for every x, y varies from [itex]-\sqrt{4- x^2}[/itex] to [itex]\sqrt{4- x^2}[/itex]. Or write it in polar coordinates with r going from 0 to 2, [itex]\theta[/itex] from 0 to [itex]2\pi[/itex].

For every point (x, y), the z-coordinate varies from [itex]x^2[/itex] to [itex]9- x^2[/itex] just as you are told.
 

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