How Do You Calculate the Upward Force Needed to Keep a Board Level?

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To calculate the upward force T needed to keep a uniform board level, consider the board's weight of 6N and its length of 90 cm, pivoted at one end. The weight acts at the center of mass, which is located at 45 cm from the hinge. By taking moments about the hinge, the torque due to the weight must equal the torque due to the upward force T. The upward force T can be determined by setting the torques equal and solving the equation. A free body diagram can aid in visualizing the forces and moments involved in this statics problem.
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A uniform board of length 90 cm is pivoted at a hinge at one end. It is kept level by an upward vertical force T applied at the opposite end. The weight of the board is 6N.
Take moments about the hinge to find T, when the board is level.
The hinge exerts an upward force, F on the board. Equate parallel forces to determine F when the board is level.

All inputs in understanding this question and the steps to solve it will be great help. Thank you.
 
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It's a board which weighs 6N. It is supported by a hinge at one end and an upward force at the other. Assume the weight of the board is evenly distributed over its length. Draw a free body diagram and solve for T.

This is a simple statics problem.
 
@ SteamKing - Thank you for your response. Can you please elaborate and work it out for me?
 
gomathireddy said:
Can you please elaborate and work it out for me?
That's not how things work here. You post your attempted solution and I'm sure you'll get plenty of advice and corrections.

Please see: How to Ask for Help
 
Hi, assuming i understand this correctly , here are some hints:

Torque = f x d

The weight acts at the Centre of Mass

Make sure the torque balance.

Cheers,
oneplusone
 
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