How Do You Calculate Vertical Forces on Beam Supports with a Piano?

  • Thread starter Thread starter kp87
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
To calculate the vertical forces on beam supports with a piano, the problem involves a 75 kg beam supported at both ends with a 275 kg piano placed a quarter of the way from one end. The correct approach is to set the sum of moments around the support farthest from the piano to zero, incorporating both the weight of the piano and the beam. Initially, incorrect calculations were made, but the correct forces were identified as 1042 N for the support farthest from the piano and 2391 N for the closest support. It is crucial to include the weight of the beam in the calculations for accurate results. Proper notation and moment calculations are essential for solving such problems effectively.
kp87
Messages
7
Reaction score
0

Homework Statement


A 75.0 kg horizontal beam is supported at each end. A 275 kg piano rests a quarter of the way from one end. What is the vertical force on the support closest to the piano?
What is the vertical force on the support farthest from the piano?

Homework Equations


Tcw=Tccw



The Attempt at a Solution


I tried using Tcw=Tccw
so Fpiano*r1+Fbeam*r2=Fbeam*r3
so 275*9.81*3/4+75*9.81*1/2=Fb*1
So I got 2391N for the farthest beam
and 275*9.81*1/4+75*9.81*1/2=Fb*1
and got 1042N for the closer one but they seem to be wrong...
can you guys help me on this?

nvm... I got the answer now I did it backwards so the one with 1042N is farthest and 2391N is the closest...
thanks lol
 
Last edited:
Physics news on Phys.org
Simplify your notation. Let A be the reaction force at the support closer to the piano (let's say, the left one), and B the other reaction force. Then set the sum of moments around support B (the one further from the piano) equal to zero. Let the length of the beam be L.

Edit: don't forget to count the weight of the beam (whose resultant is acting at the center of the beam) in your calculation.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Torque Rigid Beam: Find Force Applied by Support 2
Replies
4
Views
2K
Equilibrium of Forces and Torques on Sawhorses Supporting a Person on a Board
Replies
6
Views
2K
Find required distance of support for beam
Replies
10
Views
5K
How Do You Calculate Forces and Balance a Hanging Cafe Sign?
Replies
18
Views
3K
What are the cord tension and force on the hinge for this angled beam?
Replies
4
Views
2K
How Do You Calculate the Acceleration of This Inflated Balloon?
Replies
4
Views
2K
Max Load Force on Uniform Pine Beam of 3.6m & 25kg | Safety Factor 5.0
Replies
1
Views
2K
Mover Pushes 700 kg Piano up 9° Ramp - Force Calculation
Replies
4
Views
1K
How Is the Vertical Force Calculated at the Hinge in a Beam and Sign System?
Replies
8
Views
6K
Beam and Support Force Question
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top