How Do You Calculate Work Done to Overcome Friction on an Inclined Plane?

AI Thread Summary
To calculate the work done to overcome friction on an inclined plane, the discussion centers on a block with a mass of 30 kg sliding down an 8 m long incline at a 28-degree angle with an acceleration of 1.5 m/s². The work done against friction was calculated to be approximately -745.36 J, leading to questions about the relationship between work, kinetic energy, and potential energy. Participants suggest verifying the value of gravitational acceleration used in calculations, as discrepancies may arise from different assumptions. The conversation emphasizes the importance of correctly applying the free-body diagram equations to solve for the coefficient of kinetic friction. Understanding these relationships is crucial for accurately determining the work done against friction.
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im having a hard time to solve this work done by overcoming friction question. help please?

Question: a block with mass 30kg slide on a rough inclined plane with 8m long and 28 degree to horizontal with acceleration 1.5ms^-2.
a)Calculate the work done to overcome friction.
b)the coefficient of kinetic friction between the block and the plane
 
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Start by writing down the free-body diagram equations.
 
done that and got kE=360.15J
 
And how does this help?
 
well,the answer for work done to overcome friction is WFf= -745.36J. wonder why was that.
 
What is the relationship between work, kinetic and potential energy?
 
it helps abit but i got (-745.17J) tho
 
What value are you using for g (gravitational acceleration)? Perhaps the problem statement is using a different value than what you're using.
 
k thanks for your help.
 
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