How Do You Convert sin^2(z) into x+iy Form?

jjangub
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Homework Statement


How do I change sin^2(z) to x+iy form? (z=x+iy)
I have to put this x and y to arctan(y/x)

Homework Equations


The Attempt at a Solution


I tried to use sin^2(z) = 1/2 -1/2(cos(2z)) or sin(z) = ((e^(iz) - e^(-iz))/2i)^2
but both ways I cannot take out i.
Or isn't the sin only takes the imagenary part? so there is no x and only y exists.
It brings us that artan(0) = 0?
I am confused about these cases like when there is sin(z) and cos(z)...
Thank you.
 
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z is real?
 
How would you expand Sin(x + i y)?
Using a trig identity.
 
jjangub said:

Homework Statement


How do I change sin^2(z) to x+iy form? (z=x+iy)
I have to put this x and y to arctan(y/x)

Homework Equations


The Attempt at a Solution


I tried to use sin^2(z) = 1/2 -1/2(cos(2z)) or sin(z) = ((e^(iz) - e^(-iz))/2i)^2
but both ways I cannot take out i.
Or isn't the sin only takes the imagenary part? so there is no x and only y exists.
It brings us that artan(0) = 0?
I am confused about these cases like when there is sin(z) and cos(z)...
Thank you.

that's not how it works
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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