How Do You Derive the Final Equation for Displacement and Time?

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The discussion focuses on deriving the final equation for displacement and time, specifically addressing the correct formulation of kinematic equations. The initial equation presented, v(t) = v_0 + (1/2) a t^2, is corrected to x(t) = x_0 + v_0 t + (1/2) a t^2 and v(t) = v_0 + a t. Participants emphasize the importance of understanding the relationship between acceleration, velocity, and displacement through calculus, particularly simple integrations. There is an acknowledgment of the challenges faced when re-engaging with math concepts after a break. Overall, the conversation highlights the process of deriving kinematic equations and the need for a solid grasp of foundational math skills.
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In order to get this final equation
of Displacement and time: v(t) = v_0 + \frac{1}{2} a t^2


How would I come about actually making this equation?

Would it be a combination of the simple acceleration equation and Delta x equation ... with so algebra. BOOM answer?


Thanks for your help!

--- Anita
 
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um... actually that isn't a correct equation. Were you thinking of one of these?
\begin{align*}<br /> x(t) &amp;= x_0 + v_0 t + \frac{1}{2}a t^2 \\<br /> v(t) &amp;= v_0 + a t<br /> \end{align*}
 
Oh, crap yes! The first one :)
 
http://www.coolschool.ca/lor/PH11/unit2/U02L02/kinematic5.gif"
make sure you understand it:cool:
 
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WOW, that's how you do that! UH, I hate not having math hard core in my life and then BAM all of a sudden need to use it.

Thanks a million :) !
 
Anita08 said:
Oh, crap yes! The first one :)

Are you comfortable with doing integrals in calculus? You use fairly simple integrations to go from a(t) --> v(t) --> x(t), assuming constant acceleration (which is true in this case of gravity being the acceration).
 
I used to about two years ago :(

I'm lost at times but definitely getting there!
 
any time :smile:
 
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