How Do You Differentiate f(x) = (71+x)/(1-x)?

AwesomeSN
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Homework Statement



Differentiate, f(x)=71+x/1-x

Homework Equations


The Attempt at a Solution



Working this out, hoping it's right as I was going along, my final answer is 71+x/1-x * (2ln7)/1-x
 
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Check your denominator...

Looks like you may have had a bit of a problem after you applied the chain rule. A great way to check your answers is to plug them in on www.wolframalpha.com. If you are incorrect, you can always ask us about the accuracy of your steps.
 
AwesomeSN said:

Homework Statement



Differentiate, f(x)=71+x/1-x

Homework Equations





The Attempt at a Solution



Working this out, hoping it's right as I was going along, my final answer is 71+x/1-x * (2ln7)/1-x

Please learn to typeset expressions properly; in particular, USE PARENTHESES. Your function is f(x) = 7(1+x)/(1-x). What you wrote actually means 71 + (x/1) -x = 7.

RGV
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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