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How do you divide a polynomial by (x+1)

  1. Sep 15, 2008 #1
    1. The problem statement, all variables and given/known data
    Let p(x)= (x+1)(x-3)Q(x) + a(x+1)+b

    Where q(x) is a polynomial and a and b are real numbers

    When p(x) is divided by (x+1) the remainder is 1, what is the value of b

    I'm revising year 12 mathematics and I've forgotten how to divide polynomials
    Is it

    If I divided (x+1) by p(x) is it just = (x-3)q(x) + a + b so does that mean a+b is the remainder so a+b=1 therefore a = 1-b ?

    Is that even close? :)
  2. jcsd
  3. Sep 15, 2008 #2
    You seem to have divided OK for the first two terms, but doesn't b get divided by x + 1 as well?

    As x varies then how can the remainder *always* be 1?
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