How do you divide a polynomial by (x+1)

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SUMMARY

The discussion centers on dividing the polynomial p(x) = (x+1)(x-3)Q(x) + a(x+1) + b by (x+1) and determining the value of b given that the remainder is 1. Participants clarify that when dividing by (x+1), the remainder is derived from the constant term, leading to the equation a + b = 1. The confusion arises regarding the treatment of the terms a and b in the division process, emphasizing the need for a clear understanding of polynomial division principles.

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Homework Statement


Let p(x)= (x+1)(x-3)Q(x) + a(x+1)+b

Where q(x) is a polynomial and a and b are real numbers

When p(x) is divided by (x+1) the remainder is 1, what is the value of b


I'm revising year 12 mathematics and I've forgotten how to divide polynomials
Is it

If I divided (x+1) by p(x) is it just = (x-3)q(x) + a + b so does that mean a+b is the remainder so a+b=1 therefore a = 1-b ?

Is that even close? :)
 
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You seem to have divided OK for the first two terms, but doesn't b get divided by x + 1 as well?

As x varies then how can the remainder *always* be 1?
 

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