How Do You Find the First Time Position and Velocity Reach Their Maximum Values?

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To find the first time when position and velocity reach their maximum values, the cosine function in the position equation must equal 1, which occurs when the angle is 0 or a multiple of 2π. This leads to the equation 4.094t + 0.14π = 2nπ, where n is an integer. Solving for t gives the first positive time for maximum position. For maximum velocity, the sine function in the velocity equation must equal 1, leading to the equation 4.094t + 0.14π = π/2 + 2mπ, where m is also an integer. The solutions to these equations provide the required times for maximum position and velocity.
lefthand
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this here is the problem...

Use the equations below. (Note that the direction is indicated by the sign in front of the equations.)
x = (0.0553 m) cos(4.094t + 0.14π)

v = −(0.226 m/s) sin(4.094t + 0.14π)

a = −(0.927 m/s2) cos(4.094t + 0.14π)

(a) Determine the first time (t > 0) that the position is at its maximum (positive) value.
s

(b) Determine the first time (t > 0) that the velocity is at its maximum (positive) value.
s

i have no idea where to start, or how to do this.
 
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Position is given by x.

At what angle is the cos(...) maximum?
 
they didnt give an angle. but I'm guessing since we want x to equal what ever number is there, then cos must equal 1 right?
 
so (0.0553 m) cos(4.094t + 0.14π) is max when cos(4.094t + 0.14π) = 1

that is when (4.094t + 0.14π) = ...?
 
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