How Do You Integrate 4cos(n pi t)?

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Homework Statement



integrate:
4*cos(n pi t) d(t)

Homework Equations


The Attempt at a Solution



is it: [4sin(n pi t)]/n.pi

or

[4t sin (n pi t)]/n.pi

any help very much welcome.
 
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What do you get if you differentiate those?

\int cos(u)du= sin(u)+ C[/edit]. What should you let u be? What is du?
 
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HallsofIvy said:
What do you get if you differentiate those?

\int cos(u)du= sin(u)+ C
. What should you let u be? What is du?[/QUOTE]<br /> <br /> Thanks for your quick reply, but you have lost me
 
would u = 4

therefore du=0
 
Look at your given and the general solution:

\int 4cos(n\pi t) dt

\int cos(u)du = sin(u)+ C

Notice the similarity.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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