How Do You Integrate 59x(cos(x))^2?

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Homework Statement



\int 59x(cos(x))2 dx


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The Attempt at a Solution



I tried doing integration by parts with u= (cos(x))2 and dv= xdx
v= \frac{x^2}{2}
However this didnt get me very far can some one tell me what the first step or two are.
 
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I got the the answer to be 59(\frac{1}{4}x sin(2x) + \frac{1}{8}cos(2x) + \frac{x^2}{4})
But this was from my calculator I still don't know how to do it.
 
Use:

\cos^2(x) = \frac {1 + \cos{(2x)}}{2}

and integration by parts.
 
ok Ill check it out thanks
 
OK I tried it and it just got more complicated. Whats the next step?
 
what LCKurtz suggested shoudl lead to a pretty simple integral, maybe show what you did
 
just did x(1+co(2x)/(2))
Do i distribute or use by parts now?
 
yep multiply out and use parts on the (x.cos(2x)) part
 
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