How Do You Prove Sets Have Cardinality Aleph-Nought?

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To prove that the sets {1/(2^k) : k∈ℕ} and {x∈ℤ : x >= -5} have cardinality aleph-nought, establish a one-to-one correspondence with the natural numbers. For the first set, list its elements, demonstrating that each can be paired with a natural number. The second set includes integers starting from -5 and can also be paired with natural numbers. The key is to show that both sets can be matched with the sequence of positive integers. This method effectively demonstrates their countable nature.
dhillon
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URGENT HELP PLEASEEEE, a question on set theory

Homework Statement


the question is:

Prove that these sets have cardinality aleph-nought:(there is two 2 prove)

(a) {1/(2^k) : k∈ℕ}

(b) {x∈ℤ : x >= -5}


im not sure how to work this out, please help on this, i did ask on a previous thread how to prove cardinality of a statement, thanks for your help guys
 
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dhillon said:

Homework Statement


the question is:

Prove that these sets have cardinality aleph-nought:(there is two 2 prove)

(a) {1/(2^k) : k∈ℕ}

(b) {x∈ℤ : x >= -5}


im not sure how to work this out, please help on this, i did ask on a previous thread how to prove cardinality of a statement, thanks for your help guys
I'm using IE8, which doesn't display some symbols. For a, I'm guessing that it says that k is a positive integer. I have no idea what the two symbols after x are in the b part.

To show that the cardinality of a set is Aleph-nought, show that there is a one-to-one pairing between the elements in the set and the positive integers.
 


hey thanks for trying to help, I truthfully have no idea on how to do this,

part a) k is an element of natural number e.g 1,2,3,4...
part b) x is an element of integers e.g -3,-2,0,1,2,3...

if this has helped please let me know
 


dhillon said:
hey thanks for trying to help, I truthfully have no idea on how to do this,
Did you miss the second paragraph in my post?
dhillon said:
part a) k is an element of natural number e.g 1,2,3,4...
part b) x is an element of integers e.g -3,-2,0,1,2,3...
In part b, the set is {-5, -4, -3, ..., 0, 1, 2, 3, ...}
 


oh ok sorry i missed that, i'll try, thanks for the help, i was trying since morning but I am not sure that's the thing, i'll keep trying though, do you know how to work this out by any chance? because I am soo stuck :( , thank you
 


Yes, I know how to do them. Neither one requires much work. The first one is almost obvious.

For a, write the set in expanded form, starting with the first member and continuing for 5 or 6 members. Show that each member in this set can be associated with one of the numbers in the set {1, 2, 3, 4, ...} and be able to show the pairing for an arbitrary member of your first set.

It's very similar for the b part.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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