How Do You Rotate and Stretch a Complex Number Vector?

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Homework Help Overview

The problem involves rotating a vector represented by a complex number in the Cartesian plane and then stretching it. Specifically, the original vector OA is given as A(2√3,1), and the task is to rotate it by 30° clockwise and stretch it by a factor of 6 to find the coordinates of point B.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use Euler's form and expresses confusion regarding the argument of the complex number. They also explore the representation of the angle in surd form after rotation.
  • Some participants suggest drawing the vector to visualize the problem and question the steps taken by the original poster.
  • There is a discussion about expressing the rotation as multiplication by a complex number and the implications of scaling and rotation in complex number operations.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to approach the problem without giving direct solutions. There is an emphasis on showing work and clarifying steps taken in the reasoning process.

Contextual Notes

Participants note that the original poster's notes lack explanations on the multiplication of complex numbers for scaling and rotation, which may be contributing to their confusion.

AlexChan
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Given A(2√3,1) in R^2 , rotate OA by 30° in clockwise direction and stretch the resulting vector by a factor of 6 to OB. Determine the coordinates of B in surd form using complex number technique.

i try to rewrite in Euler's form and I found the modulus was √13 but the argument could not be represented in radian, so i feel confuse to cope with this question.:frown:

MENTOR Note: moved here from Linear Algebra hence no template
 
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Did you try drawing it to see where you went wrong?
 
jedishrfu said:
Did you try drawing it to see where you went wrong?

yes, i draw the it in 2d plane with real and img. axis and roughly get the resulting vector, but still confuse with getting the exact number of the argument
 
Can you show us what you did step by step?

On this site,we can't help you unless you show some work.
 
jedishrfu said:
Can you show us what you did step by step?

On this site,we can't help you unless you show some work.
1.PNG

sorry for my bad work.
the above is the roughly work. I found the angle(argument) between OA and x-axis (real axis) was tan^-1(1/2√3)≈16.10211375
After rotate 30° clockwise, the angle between OB and x-axis was 16.10211375-30≈-13.89788625
and here i got trouble with the representation in surd form.
OA = 2√3+i =√13(cos16.10211375+isin16.10211375)
I found that complex number multiplication represent scaling and rotation, but my notes didnt contain explanation of this part
 
So the rotated number is sqrt(13)*(cos(-13.89) + I sin(-13.89) ) right?

Then take the negative out of the sin and cos to get it into better form.

Next you have to make it 6 times bigger.
 
AlexChan said:
Given A(2√3,1) in R^2 , rotate OA by 30° in clockwise direction and stretch the resulting vector by a factor of 6 to OB. Determine the coordinates of B in surd form using complex number technique.

i try to rewrite in Euler's form and I found the modulus was √13 but the argument could not be represented in radian, so i feel confuse to cope with this question.:frown:

MENTOR Note: moved here from Linear Algebra hence no template

The argument can be expressed in radians, but you need not bother doing that. Just express the clockwise 30° rotation as multiplication by a complex number of the form a + bi and then carry out the operations of standard complex-number multiplication. Your final answer need not involve any approximate decimal numbers, but can be expressed exactly in terms of square roots and the like.
 
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