How Do You Rotate and Stretch a Complex Number Vector?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
6 replies · 2K views · last reply
AlexChan
Messages
3
Reaction score
0
Given A(2√3,1) in R^2 , rotate OA by 30° in clockwise direction and stretch the resulting vector by a factor of 6 to OB. Determine the coordinates of B in surd form using complex number technique.

i try to rewrite in Euler's form and I found the modulus was √13 but the argument could not be represented in radian, so i feel confuse to cope with this question.:frown:

MENTOR Note: moved here from Linear Algebra hence no template
 
Last edited by a moderator:
Physics news on Phys.org
jedishrfu said:
Did you try drawing it to see where you went wrong?

yes, i draw the it in 2d plane with real and img. axis and roughly get the resulting vector, but still confuse with getting the exact number of the argument
 
jedishrfu said:
Can you show us what you did step by step?

On this site,we can't help you unless you show some work.
Coordinate plane from -6 to 6 on both axes, with a red vector from the origin to A (2√3, 1) and an orange vector from the origin to B pointing slightly below the positive x-axis.

sorry for my bad work.
the above is the roughly work. I found the angle(argument) between OA and x-axis (real axis) was tan^-1(1/2√3)≈16.10211375
After rotate 30° clockwise, the angle between OB and x-axis was 16.10211375-30≈-13.89788625
and here i got trouble with the representation in surd form.
OA = 2√3+i =√13(cos16.10211375+isin16.10211375)
I found that complex number multiplication represent scaling and rotation, but my notes didnt contain explanation of this part
 
So the rotated number is sqrt(13)*(cos(-13.89) + I sin(-13.89) ) right?

Then take the negative out of the sin and cos to get it into better form.

Next you have to make it 6 times bigger.
 
AlexChan said:
Given A(2√3,1) in R^2 , rotate OA by 30° in clockwise direction and stretch the resulting vector by a factor of 6 to OB. Determine the coordinates of B in surd form using complex number technique.

i try to rewrite in Euler's form and I found the modulus was √13 but the argument could not be represented in radian, so i feel confuse to cope with this question.:frown:

MENTOR Note: moved here from Linear Algebra hence no template

The argument can be expressed in radians, but you need not bother doing that. Just express the clockwise 30° rotation as multiplication by a complex number of the form a + bi and then carry out the operations of standard complex-number multiplication. Your final answer need not involve any approximate decimal numbers, but can be expressed exactly in terms of square roots and the like.
 
  • Like
Likes   Reactions: AlexChan and jedishrfu