- #1
tolove
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Edit: Nevermind, figured it out. Thank you for readingOriginal problem:
Find the interval of convergence
[itex]\sum[/itex]∞n=1 xn / n * √(n) * 3n
Ratio Test, right? an+1/a
I get to here and I can't figure out how to get rid of the ns:
lim n→∞ abs(x/3)* [n*√(n) / (n+1)*√(n+1)]
Solution,
They break apart evenly:
(n/(n+1)) * (n/(n+1)**(1/2)
(also, sorry this looks terrible. I'm not sure how to use the graphics options very well yet)
Find the interval of convergence
[itex]\sum[/itex]∞n=1 xn / n * √(n) * 3n
Ratio Test, right? an+1/a
I get to here and I can't figure out how to get rid of the ns:
lim n→∞ abs(x/3)* [n*√(n) / (n+1)*√(n+1)]
Solution,
They break apart evenly:
(n/(n+1)) * (n/(n+1)**(1/2)
(also, sorry this looks terrible. I'm not sure how to use the graphics options very well yet)
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