How Do You Simplify Dimensional Analysis Equations?

AI Thread Summary
To simplify the equation [T]-2/[T], one can apply the laws of exponents in dimensional analysis. The expression can be rewritten as [T]-2 * [T]-1, which results in [T]-3. This confirms that the correct simplification of the original equation is indeed [T]-3. Understanding that 1/[T] equals [T]-1 is crucial for this process. The discussion emphasizes the importance of applying exponent rules in dimensional analysis.
Byeongok
Messages
13
Reaction score
0

Homework Statement


Hello, I am new to physics and i was wondering what i should do for the following equation to simplify it.

Homework Equations


[T]-2/[T]

The Attempt at a Solution


I tried

1/[T]3
Which I'm not sure is possible when dimensional analyzing.

EDIT: Is it
[T]-3
 
Physics news on Phys.org
Byeongok said:
EDIT: Is it
[T]-3
yes.
 
Byeongok said:

Homework Statement


Hello, I am new to physics and i was wondering what i should do for the following equation to simplify it.

Homework Equations


[T]-2/[T]

The Attempt at a Solution


I tried

1/[T]3
Which I'm not sure is possible when dimensional analyzing.

EDIT: Is it
[T]-3

If you recall that ##x^{\alpha} x^{\beta} = x^{\alpha + \beta}## and that ##\frac{1}{[T]} = [T]^{-1}##, we can see that your answer is correct.

We have ##\frac{1}{[T]^{2}} \frac{1}{[T]} = [T]^{-2 + -1} = [T]^{-3}##
 
  • Like
Likes Byeongok
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top