How do you simplify the integral after trigonometric substitution?

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Homework Help Overview

The discussion revolves around simplifying an integral involving a trigonometric substitution in a calculus context. The original integral presented is ∫e^x * √(1+e^2x) dx, which has been transformed into a trigonometric form.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to simplify the integral after performing a trigonometric substitution, expressing uncertainty about the next steps. Some participants suggest considering an ordinary substitution as an alternative approach, while others emphasize the importance of trying simpler techniques first.

Discussion Status

The discussion is active, with participants exploring different methods for tackling the integral. Guidance has been offered regarding the use of ordinary substitution, and there is a recognition of the need to evaluate the integral using trigonometric substitution.

Contextual Notes

Participants are navigating the complexities of integral calculus, particularly in the context of homework constraints and the exploration of various substitution techniques. There is an acknowledgment of the original poster's efforts and the challenges faced in progressing from one step to another.

nweis84
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I’ve got this tricky trig substitution that I’ve been trying to do as for my Calc II class. I think that I’ve done the substitution part right I just have no idea where to go from here. I’ve tried many routes including integrating by parts as well.

Please help me thank you

1.) Original question = ∫e^x * √(1+e^2x ) dx



2.) after trig substitution = ∫tanθ *[sec〗^3 θdθ

I have looked at another source for help with I believe an identical question and it integrates this and it gives me

3.) (〖sec〗^3 θ)/3 + C

So I guess all I’m really asking is how they got from step two to step three.
 
Last edited:
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Did you try the ordinary substitution u = e^x?
This gives du = e^x dx, so the integral becomes
[itex]\int \sqrt{1 + u^2} du[/itex]

This integral can be evaluated using a trig substitution.
 
no I've not tried that one yet thank you!
 
Always try the simplest techniques first before tackling an integral with the more complicated techniques like trig substitution, or integration by parts, or partial fractions. If an ordinary substitution doesn't work, at least you haven't wasted much time.
 

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