How Do You Solve the Integral ∫x/(6x-x^2)^3/2 dx Using Trig Substitution?

  • Thread starter Thread starter Oalvarez
  • Start date Start date
  • Tags Tags
    Calc 2 Integral
Click For Summary
SUMMARY

The integral ∫x/(6x-x^2)^(3/2) dx can be effectively solved using trigonometric substitution after completing the square. The expression (6x - x^2) can be rewritten as - (x^2 - 6x) = -((x - 3)^2 - 9), which simplifies the integral. The recommended approach involves substituting x - 3 with 3sin(θ) to facilitate the integration process. This method provides a clear pathway to evaluate the integral accurately.

PREREQUISITES
  • Understanding of trigonometric substitution techniques
  • Familiarity with completing the square in quadratic expressions
  • Knowledge of integral calculus and indefinite integrals
  • Ability to manipulate algebraic expressions and radicals
NEXT STEPS
  • Study the method of completing the square in quadratic functions
  • Learn about trigonometric substitution in integral calculus
  • Practice solving integrals involving radicals and powers
  • Explore advanced integration techniques such as integration by parts
USEFUL FOR

Students and educators in calculus, mathematicians focusing on integral calculus, and anyone looking to enhance their skills in solving complex integrals using trigonometric methods.

Oalvarez
Messages
2
Reaction score
0
1. I need help solving this integral, I've tried using trig substitution, but I'm getting nowhere with it.


∫x/(6x-x^2)^3/2dx



Like I said before, I tried changing the bottom to a radical and trig substituting but it doesn't seem to get me anywhere. Thanks in advanced for any help.
 
Physics news on Phys.org
Welcome to PF;
You are trying to evaluate the indefinite integral:
$$\int \frac{x}{(6x-x^2)^{3/2}}\;dx$$

Note: ##(6x-x^2)^{3/2} = x^{3/2}(6-x)^{3/2}## ... probably won't help a lot: try again but complete the square first.
 
Oalvarez said:
1. I need help solving this integral, I've tried using trig substitution, but I'm getting nowhere with it.


∫x/(6x-x^2)^3/2dx



Like I said before, I tried changing the bottom to a radical and trig substituting but it doesn't seem to get me anywhere. Thanks in advanced for any help.
Please show your work.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
7
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
6K
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K