How Do You Solve a Two-Mass, Two-Spring System with External Harmonic Force?

  • Thread starter Thread starter qwertybob
  • Start date Start date
  • Tags Tags
    Spring System
AI Thread Summary
To solve the two-mass, two-spring system with an external harmonic force, the equations of motion are derived using Newton's second law. The equations for masses m1 and m2 are established, incorporating the spring constants k1 and k2, as well as the external force F sin(ωt). Clarification on the arrangement of the masses and springs indicates that k1 connects m1 to a fixed point, while k2 connects m1 and m2. A suggested approach involves manipulating the equations by multiplying them by a constant and combining them to simplify the system. This method aims to express the system in a standard form that facilitates finding the free oscillation frequencies.
qwertybob
Messages
2
Reaction score
0

Homework Statement



I have a two spring 2 mass system, with masses m1 and m2, spring constants k1 and k2. There is also an external harmonic force acting on m2, F sin(\omega\ t )

I have to obtain the free ocsillation frequencies \omega_{1} and \omega_{2}

Homework Equations




The Attempt at a Solution



i obtained the following eqns by applying Newtons 2nd law to each of the masses

m_{1}x_{1}'' = -k_{1}x_{1}+k_{2}(x_{2}-x_{1})

m_{2}x_{2}'' = -k_{2}(x_{2}-x_{1})+F sin(\omega\ t)

and this is where i am stuck, the notes I have suck tbh and i have no idea what to do next, would be very greatfull for some help.
 
Physics news on Phys.org
Welcome to PF!

qwertybob said:
I have a two spring 2 mass system, with masses m1 and m2, spring constants k1 and k2. There is also an external harmonic force acting on m2, F sin(\omega\ t )

uiop qwertybob! Welcome to PF! :smile:

I don't get it …

where are the masses and the springs in relation to each other? :confused:
 
sorry i guess i should have mentioned that, hopefully this makes it clear

/////[m1]//////[m2]

k1 connects m1 to a fixed point, k2 connects m1 and m2. displacement of m1 = x1, displacement of m2 = x2.

ty for the kind welcome :smile:
 
uiop qwertybob! :smile:

(have an omega: ω :wink:)
qwertybob said:
k1 connects m1 to a fixed point, k2 connects m1 and m2. displacement of m1 = x1, displacement of m2 = x2.

ah! … a fixed point! … all is clear! :biggrin:

ok … multiply each equation by a constant, and add, so that takes the form (ax1 + bx2)'' = c(ax1 + bx2) + Gsinωt.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top