How Do You Solve for a Using the Law of Sines?

In summary: The Attempt at a SolutionI tried putting it in, but all I got was this correct, but useless equation:6511/7990=383/470In summary, the student tried to solve for a but got an equation that was useless.
  • #1
MathWA
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Homework Statement



Find a by using The Law of Sines by knowing that c=12, angle A=42o, angle C=69o.

Homework Equations


(sin A)/a=(sin B)/b=(sin C)/c

The Attempt at a Solution


I tried putting it in, but all I got was this correct, but useless equation:
6511/7990=383/470
I did it 1 more time, but still it wasn't successful. :frown:
Please Help!
 
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  • #2
I am not sure how you go the numbers you did in the solution attempt. The sine of the angles will give you numbers less than 1. I get the answer 8.6 for a
 
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  • #3
Well, I did a lot of factoring with decimals, so I must had got them mixed up.
By the way calculators are allowed.
 
  • #4
The answer is actually 9.34, but I need the solution(step-by-step work).
 
  • #5
Show me your work.
 
  • #6
rpthomps said:
I am not sure how you go the numbers you did in the solution attempt. The sine of the angles will give you numbers less than 1. I get the answer 8.6 for a

I recalculated and got 61, instead, but its wrong!
 
  • #7
Well, I got c equals to 50.
 
  • #8
Can you write out line by line what you are doing, please?
 
  • #9
rpthomps said:
Can you write out line by line what you are doing, please?
That would take a while, but sure, but not now(I'm very busy)
I can give you the last couple of lines:
(0.94)/a=47/ac
c=50
0.94/a=0.77/50
47=0.77a
a is about 61
 
  • #10
well, firstly if 0.94 is your answer to sin42, that isn't right. I get something closer in radian mode.
 
  • #11
Oops, I typed the wrong problem!
c is 12, angle A is 110, and angle C is 50
Sorry about that rpthomps!
 
  • #12
MathWA said:
That would take a while, but sure, but not now(I'm very busy)
I can give you the last couple of lines:
(0.94)/a=47/ac
c=50
0.94/a=0.77/50
47=0.77a
a is about 61

So, is this work using the new values then? where did 47 come from?
 
  • #13
$$\frac{a}{sin110}=\frac{12}{sin50}$$

This is how I would start it. THen I would use algebra to solve for the unknown.
 
  • #14
I figured the problem out! Thank you, rpthomps!:smile::smile::smile:
 
  • #15
I made the problem too confusing!
 
  • #16
MathWA said:

The Attempt at a Solution


I tried putting it in, but all I got was this correct, but useless equation:
6511/7990=383/470
Yes, this is useless. Since you're trying to solve for a, your equation here should have a in it somewhere.
MathWA said:
The answer is actually 9.34, but I need the solution(step-by-step work).
That's not how it works here. We'll help you get to a solution, but we aren't going to give it to you step by step.

Start with what rpthomps write in post #13.
 
  • #17
MathWA said:
I figured the problem out! Thank you, rpthomps!:smile::smile::smile:
You're welcome
 

FAQ: How Do You Solve for a Using the Law of Sines?

What is the Law of Sines?

The Law of Sines is a mathematical rule used to find the relationship between the angles and sides of a non-right triangle. It states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant for all sides and angles in a given triangle.

When is the Law of Sines used?

The Law of Sines is used when given the measures of two angles and one side of a triangle and needing to find the measures of the remaining sides and angles. It is also used when given the measures of three sides of a triangle and needing to find the measures of the angles.

What is the formula for the Law of Sines?

The formula for the Law of Sines is sin(A)/a = sin(B)/b = sin(C)/c, where A, B, and C represent the angles of the triangle and a, b, and c represent the lengths of the sides opposite those angles, respectively.

Can the Law of Sines be used to solve any triangle?

No, the Law of Sines can only be used to solve triangles that satisfy the given conditions. These conditions include having at least two angles and one side known, and the angle opposite the known side must be acute or obtuse (not right).

Are there any limitations to the Law of Sines?

Yes, the Law of Sines can only be used for non-right triangles. It also does not work for all possible combinations of angles and sides. In some cases, there may be multiple solutions or no solutions at all.

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