How Do You Solve for Final Velocity in the Energy Equation Without Mass?

  • Thread starter Thread starter Matt_AMG
  • Start date Start date
  • Tags Tags
    Energy
AI Thread Summary
To solve for final velocity in the energy equation 0.5mv^2 = 0.5mv^2 + mgy without mass, the mass can be canceled out, leading to the equation Vf^2 = Vo^2 + 2gy. However, a crucial factor of 0.5 was omitted in the rearrangement, resulting in an incorrect formulation. The correct equation should maintain the 0.5 factor, resulting in 0.5Vf^2 = 0.5Vo^2 + gy. Some participants advocate for plugging in numbers before rearranging equations, despite potential round-off errors, as it simplifies the problem. The discussion highlights the importance of careful algebraic manipulation in physics equations.
Matt_AMG
Messages
1
Reaction score
0
The question I have is trying to solve the final velocity in an energy equation that goes like this: 0.5mv^2=0.5mv^2+mgy (The final velocity being on the LS).

I'm not given the mass of the skier going down the hill so I divide to cancel the mass out. I then rearrange to get Vf^2 = V^2+gy. I've pretty much nailed it down to a simple algebra problem but I can't see what's wrong!

Oh, I might add that I always plug numbers in before rearranging equations but my teacher doesn't like me doing that.
 
Last edited:
Physics news on Phys.org
Matt_AMG said:
The question I have is trying to solve the final velocity in an energy equation that goes like this: 0.5mv^2=0.5mv^2+mgy (The final velocity being on the LS).

I'm not given the mass of the skier going down the hill so I divide to cancel the mass out. I then rearrange to get Vf^2 = V^2+gy. I've pretty much nailed it down to a simple algebra problem but I can't see what's wrong!

Oh, I might add that I always plug numbers in before rearranging equations but my teacher doesn't like me doing that.
You canceled out the 'm's' just fine, but what you're left with is
0.5V_f^2 = 0.5V_o^2 + gy you left out that 0.5 factor.
BTW, I always plug in numbers before rearranging equations. It sometimes leads to round off errors, but it sure makes the algebra a lot simpler and less confusing, because it's generally much easier to deal with numbers rather than letters, but don't tell teacher I said that!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top