How Do You Solve for the Time Given Initial Velocity and Angle?

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To solve for the time a baseball reaches its highest point when thrown at a 45-degree angle with an initial speed of 19 m/s, the relevant equations include V^2 = Vi^2 + 2(a)(y) and y = (Vi)(t) + 1/2(a)(t^2). The calculated maximum height is 9.21 meters, achieved using the first equation. The time to reach this height is determined to be 1.37 seconds, confirmed through the equation V_f = V_i + at, where the final velocity at the peak is zero. A simpler approach could have been utilized for efficiency, but the solution is correct.
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Homework Statement


A left-handed pitcher at sea level throws a baseball at a 45o angle with an initial speed of 19 m/s. The time for the ball to reach its highest point can be found from the data and known constants using which equations? Solve for the time.



Homework Equations


V^2 = Vi^2 + 2(a)(y)
y = (Vi)(t) + 1/2(a)(t^2)


The Attempt at a Solution


V^2 = Vi^2 + 2(a)(y)
0 = 13.435^2 + 2*9.8*y
y = 9.21 meters

9.21 = 0 + 0.5*9.8*t^2
9.21 = 4.9*t^2
t = 1.37 seconds
 
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Yes, correct, but you could have shortened your work by using just one simpler equation. Can you identify that equation?
 
Looks okay.
I used this:
V_{f}=V_{i}+at

velocity at the highest point is 0, so..

0m/s =19m/s sin45°-9.8m/s^{2} *t
t=1.37s
 
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