How Do You Solve Spring and Force Calculations in Physics?

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The discussion focuses on solving a physics problem involving a 1 kg mass hanging from a spring with a specified spring constant and compression. Key points include calculating the weight displacement, equilibrium position, and restoring force. The equilibrium position is clarified as the point where all forces balance, which is not the unstretched length of the spring. Participants express confusion about determining the weight of the extended spring and the nature of oscillation. The importance of understanding the relationship between spring extension, weight, and restoring forces is emphasized.
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1. Homework Statement
Suppose a 1 kg mass hangs from a spring with rest length of 2 m and spring constant of 100 N/m. Then, the spring is compressed by 0.5 m. Using up as the positive direction and ignoring drag, give the following with units:

(a) The weight displacement
(b) The equilibrium position
(c) The maximum length
(d) The sign of the initial restoring force
(e) The restoring force when the length of the spring is 3.15 m

2. Homework Equations
Fs = -kx
F = ma

3. The Attempt at a Solution
a) .5
b)This is what i do not know
c)also do not know
d)Fs = Force of spring
e)Fs = 100N/m *3.15m -> 315N
 
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a) What is a "weight displacement"? Your answer needs units.
b) Can you calculate the weight extending the spring? How is this related to the extension of the spring (at equilibrium) and the spring constant?
c) Quickest way: the oscillation will be symmetric around the equilibrium position.
d) The answer is a sign (+ or -).
e) Test your answer with the restoring force at a length of 2m. What do you expect?
 
a) .5m displacement is stretched - un-stretched
b) I am really confused here, I do not know how to calculate weight of extended spring. Also, where is the equilibrium, at rest length or un-stretched length?

c) How do i see the oscillation of this spring?
 
daveyboy157 said:
where is the equilibrium, at rest length or un-stretched length?
c) How do i see the oscillation of this spring?
The equilibrium position is the one where it would remain stationary if set stationary. I.e., all the forces balance. This will not be the unstretched position, because some stretch is needed to balance the force of gravity. Neither will it be the instantaneous rest position of the oscillation.
 
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