How Do You Solve These Continuous Probability Problems?

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Homework Help Overview

The discussion revolves around continuous probability problems involving a given probability density function f(x) defined for a specific interval. Participants are tasked with finding the cumulative distribution function F(x), probabilities for certain intervals, the expected value E(X), and the standard deviation of the random variable X.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants attempt to compute the cumulative distribution function and various probabilities using integrals of the given polynomial function. Some express concerns about the correctness of the formulas used and the clarity of the original poster's expressions.

Discussion Status

There are multiple interpretations of the problem, with some participants questioning the validity of certain calculations and suggesting that additional information is needed for a complete understanding. Guidance has been offered regarding the expectations for integral formulas, but no consensus has been reached on the correctness of the approaches taken.

Contextual Notes

Some participants note that the problem may have been miscategorized in the forum, indicating a potential misunderstanding of the required mathematical context.

noreturn2
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Homework Statement


f(x) = (3/4)(-x^2 + 6x - 8) for 2 < x < 4 (0 elsewhere)

A) Find F(x)

integral 2 to 4 ((3/4)(-x^2 + 6x - 8))dx

B) Use F(x) to find P(3 < X < 3.5)

integral 3 to 3.5 ((3/4)(-x^2 + 6x - 8))dx

11/32

C) Use F(x) to find P(X > 3.5)

1-( P(3 < X < 3.5)) = 21/31

D) Find E(X).

integral 2 to 4 (x*(3/4)(-x^2 + 6x - 8))dx = 3

E) Find the standard deviation of X.

integral 2 to 4 (x^2(3/4)(-x^2 + 6x - 8))dx E[x^2)-E[x] = sqrt(6.2)= 2.48
 
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They will expect you to give the formula of the integrals you mention. For the simple polynomial of this problem, you should be able to do that.
 
noreturn2 said:

Homework Statement


f(x) = (3/4)(-x^2 + 6x - 8) for 2 < x < 4 (0 elsewhere)

A) Find F(x)

integral 2 to 4 ((3/4)(-x^2 + 6x - 8))dx

B) Use F(x) to find P(3 < X < 3.5)

integral 3 to 3.5 ((3/4)(-x^2 + 6x - 8))dx

11/32

C) Use F(x) to find P(X > 3.5)

1-( P(3 < X < 3.5)) = 21/31

D) Find E(X).

integral 2 to 4 (x*(3/4)(-x^2 + 6x - 8))dx = 3

E) Find the standard deviation of X.

integral 2 to 4 (x^2(3/4)(-x^2 + 6x - 8))dx E[x^2)-E[x] = sqrt(6.2)= 2.48

(A) ##F(4) = \int_2^4 (3/4) (-x^2 + 6x - 8) \, dx,## but other values of ##F(x)## must be given by something else. What would that be?
(C) is wrong; that is to say, the formula is wrong, but I have not checked the numerical answer.
(E) is partly right, but it looks partly wrong as well; it is hard to say, since what you wrote is almost incomprehensible.
 
Thread moved to Calc & Beyond Homework section. Questions involving integrals do not belong in the Precalc section.
 

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