How Do You Use the Maclaurin Series to Evaluate the Integral of sin(3x^2)?

JayoxD
Messages
1
Reaction score
0

Homework Statement



Assume that sin(x) equals its Maclaurin series for all x.
Use the Maclaurin series for sin(3 x^2) to evaluate the integral
int_0^{0.72} sin(3 x^2) dx.
Your answer will be an infinite series. Use the first two terms to estimate its value.

Homework Equations


The Attempt at a Solution



I got

((-1)^n(3^(2n+1)0.72^(4n+3))/((2n+1)!(4n+3))
 
Physics news on Phys.org
What do you get for your Maclaurin series for sin(3x^2)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top