How Do You Write the Hamiltonian in the Basis |\theta>?

TeddyYeo
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Homework Statement



H = \frac{2e^2}{\hbar^2 C} \hat{p^2} - \frac{\hbar}{2e} I_c cos\hat\theta,
where [\hat\theta , \hat{p}] = i \hbar
How can we write the expression for the Hamiltonian in the basis |\theta>

Homework Equations

The Attempt at a Solution



I have already solved most part of the question and this is just one part of it that I am not sure how to convert into the basis form.
Is it that I just now need treat
\hat{p}] = -i \hbar ∇ which is means that it is -i \hbar frac{\partial }{ \partial \theta}
and put
H = \frac{2e^2}{C} \frac{\partial^2}{\partial\theta^2} - \frac{\hbar}{2e} I_c cos\hat\theta
then this is the final form??
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
TeddyYeo said:

Homework Statement



H = \frac{2e^2}{\hbar^2 C} \hat{p^2} - \frac{\hbar}{2e} I_c cos\hat\theta,
where [\hat\theta , \hat{p}] = i \hbar
How can we write the expression for the Hamiltonian in the basis |\theta>

Homework Equations

The Attempt at a Solution



I have already solved most part of the question and this is just one part of it that I am not sure how to convert into the basis form.
Is it that I just now need treat
\hat{p}] = -i \hbar ∇ which is means that it is -i \hbar frac{\partial }{ \partial \theta}
No. ##\hat{p^2}=-i \hbar ∇(-i \hbar ∇) =-h^2 \Delta##. Use the Laplace operator written in spherical polar coordinates.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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