MHB How Does a 30% Price Increase Affect Sales to Result in a 9% Revenue Decrease?

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A 30% price increase on a box of peanuts leads to a 9% decrease in revenue, prompting a discussion on the corresponding sales decrease, denoted as x%. The original revenue is calculated as the product of original sales and price, while the new revenue reflects a 9% loss. The new selling price is 1.30 times the original, and sales decrease to (1 - x/100) of the original sales. By equating the new revenue to the adjusted sales and price, the value of x can be determined through algebraic manipulation. The solution illustrates the relationship between price changes, sales volume, and overall revenue impact.
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when the price of a box of peanuts is increased by 30% its sales decreased by x% such that the revenue decreased by 9%.what is the value of x?
solution:
let cost price=100 ,
with an increase of 30%selling price is 130, revenue is 9% lessso he incurred a loss of 9% over the income he has to get by selling x number of articles.so...
pls help me homework to solve it.just got stuck here
 
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Let the original price be $$P_0$$, the original sales be $$X_0$$ and the original revenue be $$R_0$$.

Then $$R_0=X_0 P_0$$. Now the price is increased to $$P_1=1.30 P_0$$, and sales become $$X_1=\left(1-\frac{x}{100}\right)X_0$$ and revenue $$R_1=0.91 R_0$$.

We also have:

$$R_1=X_1P_1$$

Substituting in from the previous paragraph we get:

$$0.91R_0 = \left( 1-\frac{x}{100}\right) X_0 \times 1.30 P_0=\left( 1-\frac{x}{100}\right) \times 1.30 R_0$$

from which you can solve for [math]x[/math].
 
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