MHB How Does a 30% Price Increase Affect Sales to Result in a 9% Revenue Decrease?

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A 30% price increase on a box of peanuts leads to a 9% decrease in revenue, prompting a discussion on the corresponding sales decrease, denoted as x%. The original revenue is calculated as the product of original sales and price, while the new revenue reflects a 9% loss. The new selling price is 1.30 times the original, and sales decrease to (1 - x/100) of the original sales. By equating the new revenue to the adjusted sales and price, the value of x can be determined through algebraic manipulation. The solution illustrates the relationship between price changes, sales volume, and overall revenue impact.
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when the price of a box of peanuts is increased by 30% its sales decreased by x% such that the revenue decreased by 9%.what is the value of x?
solution:
let cost price=100 ,
with an increase of 30%selling price is 130, revenue is 9% lessso he incurred a loss of 9% over the income he has to get by selling x number of articles.so...
pls help me homework to solve it.just got stuck here
 
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Let the original price be $$P_0$$, the original sales be $$X_0$$ and the original revenue be $$R_0$$.

Then $$R_0=X_0 P_0$$. Now the price is increased to $$P_1=1.30 P_0$$, and sales become $$X_1=\left(1-\frac{x}{100}\right)X_0$$ and revenue $$R_1=0.91 R_0$$.

We also have:

$$R_1=X_1P_1$$

Substituting in from the previous paragraph we get:

$$0.91R_0 = \left( 1-\frac{x}{100}\right) X_0 \times 1.30 P_0=\left( 1-\frac{x}{100}\right) \times 1.30 R_0$$

from which you can solve for [math]x[/math].
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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