How Does a Bugler Control Frequency with Lip and Air Pressure Adjustments?

AI Thread Summary
A bugler can control the frequency of tones produced by adjusting lip tension and air pressure without altering the air column's length. The effective length of the bugle can be calculated using the formula L = v/f, where v is the speed of sound in air (346 m/s) and f is the frequency (440 Hz). This results in an effective length of 0.786 meters. The confusion arises from the relationship between wavelength and length, as the bugler's technique allows for producing multiple frequencies while maintaining the same physical length. Understanding these principles is crucial for mastering bugle performance.
halo168
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Homework Statement


By adjustin her lips correctly and blowing with the proper pressure, a bugler can cause her instrument to produce a sequence of tones, amog which are the following: 440, 660, 880, 1100, . . . Hz --- all without changing the length of the air column. (b) What is the ffective length of this bugle? (use 346 m/s for the speed of sound in air).

Homework Equations


2L = v/f

The Attempt at a Solution


I got 0.393 m with the equation 2L = v/f where v is the speed of sound through air and f is 440 m/s (effective frequency). The answer was rather 0.786 m whifch is basically L = v/f (without the 2L). Isn't lambda = 2L?
If so, where did it go?
 
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halo168 said:
a sequence of tones, among which are
Take careful note of that wording.
 
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