How Does a Charged Speck of Dust Behave in Electric and Gravitational Fields?

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A charged speck of dust with an electron charge experiences a downward gravitational field of 9.8 N/kg and a uniform electric field of 100 N/C. The electric field acts in the direction determined by the charge of the dust particle, which is negatively charged, leading to an upward force. The gravitational force consistently acts downward. The electric field does not always oppose the gravitational field; instead, its direction depends on the charge's sign. Understanding these forces is crucial for accurately drawing the corresponding diagrams.
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Homework Statement


Near to the Earth's surface, a speck of dust with a charge equal to an electron experiences a uniform downward electric field of strength 100NC-1 and a uniform gravitational field of strength 9.8Nkg-1.

a)draw a diagram showing the electric field pattern and the sign of the charge on the surface.
b)draw a free-body force diagram for the speck of dust labelling the forces.


Homework Equations


Don't think I need any for the question.


The Attempt at a Solution


a)I don't know where the other charge is. There is one charge on the speck of dust, but where does the field act?
b)I know the gravitation field will act downwards. And I think the electric field always acts in the opposite direction to the gravitation field? So it will act upwards? But then it has a negative charge (equal to electron) so that confuses me.
 
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AsksQuestions said:

Homework Equations


Don't think I need any for the question.

Right you are.

The Attempt at a Solution


a)I don't know where the other charge is. There is one charge on the speck of dust, but where does the field act?

The other charge is distributed over the surface of the Earth. And the speck of dust is suspended in a uniform electric field. That means the field acts everywhere for the purposes of this problem.

b)I know the gravitation field will act downwards. And I think the electric field always acts in the opposite direction to the gravitation field? So it will act upwards? But then it has a negative charge (equal to electron) so that confuses me.

There is no correlation between the direction of the gravitational and electric fields. The correlation is determined by the direction of the electric field and the charge of the particle suspended in the field.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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