How Does a Fluid Oscillate in a U-Tube with Mercury?

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In a U-tube containing mercury, when the fluid level is disturbed, it oscillates with a periodic time given by Tn=2pi sqrt[(m/2g'rho'a)], where 'm' is the mass of mercury, 'rho' is its density, and 'a' is the cross-sectional area. The discussion emphasizes using Newton's laws and energy methods to derive this result, drawing parallels to spring mechanics. The concept of circular frequency is mentioned, with the relationship between frequency and time period highlighted. Participants are encouraged to visualize the forces acting on the mercury column during oscillation. Understanding these principles is essential for solving fluid oscillation problems in U-tubes.
Bravemeister
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A u tube open at both ends and a uniform cross section contains a mas of mercury,m and a density of 'rho' if the level is slightly disturbed show the surface oscillates with a periodic time of

Tn=2pi sqrt[(m/2g'rho'a)]

where a is the cross sectional area.

i understand how to do this question if it were a spring with a spring constant of k or whatever but i don't know how to do it for a fluid.

I know that circular frequency is sqrt[m/m] and that the frequency is circular frequency/2pi and the time period is 1 over frequency.

the question says the desired result should be found using Newtons laws and the energy method.
 
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You have, of course, tried a google search on "u tube mercury oscillations"? :wink:
 
Think about the force of a spring stretched by a distance. Then think of the force on a column of Mercury in a condition of imbalance.
 
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