How Does a Spinning Bicycle Wheel Defy Gravity?

AI Thread Summary
A spinning bicycle wheel maintains its vertical position due to the principles of angular momentum and gyroscopic stability. When the wheel is spun, the forces acting on it create a torque that results in precession, allowing it to resist changes in orientation. Once the wheel stops spinning, it loses this stability and falls to a horizontal position. This phenomenon illustrates the fundamental concepts of rotational motion and gyroscopic effects. Understanding these principles can enhance comprehension of various physical systems and their behaviors.
AARMA
Messages
18
Reaction score
0
In a class demonstration, a bicycle wheel was held on an axle and spun. The result came to be that the wheel while rotating held a vertical position while holding it by a string attached to the end of the axle. After the wheel stopped rotating its vertical position ceased and the wheel attained a horizontal position.

How and why does that happen?
 
Physics news on Phys.org
can someone explain with his own words.. :)
 
AARMA said:
In a class demonstration, a bicycle wheel was held on an axle and spun.

On physicsforums:
See this post from november 2010 about https://www.physicsforums.com/showpost.php?p=2992527&postcount=3".


More detailed discussion is in the http://www.cleonis.nl/physics/phys256/gyroscope_physics.php" article on my website.
 
Last edited by a moderator:
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top