How Does Adding More Springs Affect Extension in Hooke's Law Experiments?

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Homework Help Overview

The discussion revolves around the application of Hooke's Law in experiments involving springs. The original poster describes a classroom activity where they measured the extension of a spring under different masses but only completed part of the required experiments. They seek guidance on how adding more springs affects extension.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of connecting springs in series versus parallel configurations, questioning the relationship between force, spring constant, and extension. Some express confusion about the original poster's reasoning regarding the extension when adding springs.

Discussion Status

Some participants have offered insights into the mechanics of spring combinations, suggesting that the original poster reconsider their assumptions about the effects of adding springs. There is an ongoing exploration of the concepts without a clear consensus on the interpretations of the questions posed.

Contextual Notes

The original poster indicates they did not complete all required experiments, which may limit their understanding of the concepts being discussed. There is also mention of conflicting information from online sources, contributing to their uncertainty.

thang08
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Homework Statement



This isn't acctually a problem but I really don't know what to do. I was doing a simple activity about Hooke's Law during class today where I have to set up a apparatus and measure the extension of spring when when we put different masses on it. I didn't do it properly so I have difficulty answering it

This is my graph if it helps any

http://img156.imageshack.us/img156/8913/clipuw9.jpg
you see, I only did the experiment with 1 spring. I didn't do the following required experiments, so I have no idea how to answer.

Homework Equations



Q6. Write how much extension do you think there would be (compared to the extension for one spring) if you now had two springs, identical to the one used, joined one after the other

Q7. Observe what happens (describe). Explain

Q8. Do the same, but this time for two springs side by side

Q9 What about three side by side, or four, or three in a row, or four?

The Attempt at a Solution



Q6. I think it remains the same because F and k remains the same => x remains
Q7. Observation would suit what I just said
Q8. 2 springs side by side so forced is distributed even onto both springs thus making the extension halved
Q9. I don't even understand the question

Thanks in advance:!)
 
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I like q8 response a lot!

So let's call a new spring constant K'eq that which satisfies the eqn,

f=-kx. the force is the same, and as you propose extention is halved,
f=-keq*.5x divide be
f=-kx and you will find k'eq=2k. For q9 extend your logic for 3 or more springs.

now q6 is a bit more subtle, but if you think more about it, you may start to doubt your answer.
 
I don't get why Q6 response is wrong, well as far as I understand force constant of a spring shows us how stiff it is. If two identical springs connected in 'series', the stiffness of the 'combined' spring doesn't change. If we don't increase the mass, i.e. no change in weight force, the extension (x) of the spring shouldn't change.
 
err, no suggestion? T_T I keep on think my way of thinking is right and some online experiment tells me that it's wrong. Explanation please
 
Been gone, think about this thought experiment forget on-line proof etc. You have a bungee like cord and want to stretch it by 2 inches. Cut the bungee cord in half and see how much more effort it requires to stretch the same 2 inches. Or if you want to save yourself a buck and have some rubberbands handy, for grins tie 4 in series and compare that with one in terms of stretch force and displacement.
The math is relatively trivial thing to prove, but I'm thinking it might be more helpful to get it out of the purely math realm. Hope this helps a bit.
 

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