Gavroy
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hi
i found the following equation that a spring(with constant k) , a mass m rotating with angular velocity ω, will have a constant angle \alpha to the vertical axis that is given by
cos(\alpha)=\frac{g}{\omega^2 l}(1-\frac{m \omega^2}{k})
this looks similar to something like cos(\alpha)=F_{gravitation}/F_{centripetal}-F_{gravitation}/F_{spring} but i do not see the geometrical idea behind this.
i am not sure whether this equation is correct at all, I found it in my physics schoolbook
i found the following equation that a spring(with constant k) , a mass m rotating with angular velocity ω, will have a constant angle \alpha to the vertical axis that is given by
cos(\alpha)=\frac{g}{\omega^2 l}(1-\frac{m \omega^2}{k})
this looks similar to something like cos(\alpha)=F_{gravitation}/F_{centripetal}-F_{gravitation}/F_{spring} but i do not see the geometrical idea behind this.
i am not sure whether this equation is correct at all, I found it in my physics schoolbook