How Does CCD Offset Affect Laser Beam Exit Angle?

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    Laser Stability
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The relationship between CCD offset and laser beam exit angle is influenced by the setup, particularly the positioning of the laser source and the CCD. When both are in focus, there is no offset; however, instability occurs when the beam's central coordinates fluctuate in the focal plane. The vertical position of the laser becomes irrelevant if the camera is focused at infinity, allowing for consideration of rays passing through the lens center. The displacement of the beam can be calculated using the sine of the angle multiplied by the focal length. Understanding these dynamics is crucial for improving laser pointing stability.
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hi,
I'm measuring my laser pointing stability with a focusing lens and a CCD.
Could you guys tell me what would the relationship be between the offset from focal point in CCD and the angle with which the beam exits the laser?

CCD is in focus.
 

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That depends on your setup. If the laser source is in the focus (as well as the CCD), there is no offset at all - that is the idea of the focus,
 
light source is about 2 meters from the ccd with a lens 10cm before the camera (100 mm f).
software fits a gaussian to an image of the beam and tells me the central coordinates. Now I see that the laser is unstable in a way that the centrum of the Gaussian moves up and down in the focal plane, meaning that the beam hits the lens sometimes higher/lower than the middle. I'm trying to relate the angle from the source to that offset (see the attachment) in μradians.
 
Okay, so focus of the camera is basically set to infinity. Then the vertical position of the laser does not matter (in an ideal camera) and you can consider rays going through the center of the lens. The displacement is just sin(angle)*focal length.
 
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