How Does Charge Distribution Affect Electric Fields in Nested Spheres?

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The discussion centers on the electric field generated by a solid sphere and a surrounding conducting shell. The solid sphere, with a radius of 3.00 cm and a net charge of +4.33 fC, is not a conductor, which is a key point of confusion. The conducting shell, with a net charge of -4.33 fC, influences the electric field distribution. At a distance of r = a/2 from the center of the sphere, the electric field is not zero due to the solid sphere's charge. Understanding the distinction between conductors and non-conductors is crucial in determining electric field behavior in this scenario.
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A solid sphere of radius a = 3.00 cm is concentric with a spherical conducting shell of inner radius b = 2.00a and outer radius c = 2.40a. The sphere has a net uniform charge q1 = +4.33 fC; the shell has a net charge q2 = –q1.

What is the magnitude of the electric field at a distance r = a/2 from the center of the sphere?

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Well, I thought the answer was 0 because as I know, the electric field inside a conductor is zero, and the sphere is a conductor. So anywhere in the sphere will have zero charge, since all the charge moves to the surface of the sphere. But, the answer is not zero. Why is this? I'm just so entirely confused with when E is zero and when it is not.

Thanks.
 
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It was not said that the solid sphere was a conductor.

ehild
 
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