How Does Delta S Relate to Proper Time in Special Relativity?

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Homework Statement


If the spacetime interval (delta S)^2 > 0, show that delta t=deltaS/c is the proper time between the two events.


Homework Equations


Can anyone please explain to me how I should be approaching this problem. I have been working on it for a while with no success. I was able to do the problem before it easily, which was "use Lorentz' equations to prove that delta S is invariant", but this one is giving me trouble.


The Attempt at a Solution

 
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I guess I worded the problem incorrectly. It should read "for ds^2 >0, show that tau=ds/c is the proper time".
 
nwdavis1 said:

Homework Statement


If the spacetime interval (delta S)^2 > 0, show that delta t=deltaS/c is the proper time between the two events.


Homework Equations


Can anyone please explain to me how I should be approaching this problem. I have been working on it for a while with no success. I was able to do the problem before it easily, which was "use Lorentz' equations to prove that delta S is invariant", but this one is giving me trouble.


The Attempt at a Solution


By definition, th eproper time is the time between two events in the frame where the two events occur at the same position. So all you have to say is that when you are in the frame where \Delta x =0 then \Delta t = \tau. Plug that in the spacetime invariant and you get the answer. Note that this definition works only for events for which (\Delta s)^2 \geq 0.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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