How does dynamic pressure affect static pressure?

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Dynamic pressure generated by flow does not affect the net force on the piston when the velocity is constant. The net force is determined by the pressure difference between the vacuum behind the piston and the atmospheric pressure outside, calculated at 2116.8 lbs. While dynamic pressure is relevant in changing flow conditions, it remains a relative measure when velocity is constant. Real-world factors like friction and viscosity would slightly alter the pressure at the piston, but these are not the focus of the current calculation. Therefore, the net acting force remains primarily influenced by the atmospheric pressure difference.
rcoopster
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I have attached another diagram, and in the diagram I show a round piston with a 1 sq ft surface area pushing water through the pipe out into to open atmosphere at 14.7 psi at a constant velocity of 75 ft/sec. There is a vacuum behind the piston, and I have calculated a 37.9 psi dynamic pressure being generated by the flow.

My question is: Based upon the dynamic pressure generated by the flow, the atmospheric outside the pipe, and the vacuum behind the piston plate, (ignoring the viscosity of the flow and the pipe walls) what will the net acting force be on the piston plate?

Will it simply be 2116.8 lbs, which is the pressure difference between the vacuum and the outside atmospheric pressure, or does the dynamic pressure or momentum of the flow have any affect?

Thank you,

rcoopster
 

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  • Dynamic and Static Pressure Diagram.JPG
    Dynamic and Static Pressure Diagram.JPG
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Any Thoughts would be greatly appreciated, thanks!
 
The dynamic pressure will not have an effect on the net force acting on the piston. Dynamic pressure effects only occur when the velocity of a gas or fluid is changed. If the velocity is constant, then dynamic pressure is just a number relative to some frame of reference. This is ingoring issues like friction with the walls of the pipe and viscosity in the water. In the real world, the pressure at the piston would have to be slightly greater than 1 atm, and pressure would decrease slightly with distance the water travels in the pipe due to friction and viscosity.
 
Does this mean that the net acting force on the piston would be equal to the 2116.8 lb atmospheric pressure difference?

thanks,

Rcoopster
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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