How Does Earth's Magnetic Field Flux Change with Loop Orientation?

AI Thread Summary
The discussion focuses on calculating the magnetic flux of Earth's magnetic field through a square loop under different orientations. The magnetic field strength is given as 5.00 x 10^-5 T, and the area of the loop is 40.0 cm². The first calculation is incorrect due to a misunderstanding of unit conversion, as 40 cm² should be converted to 0.004 m², not 0.4 m². The second calculation also fails because it relies on the incorrect first result and misapplies the cosine function for the angle. Accurate unit conversion and understanding the relationship between area and magnetic flux are crucial for solving the problem correctly.
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Magnetic flux!

Homework Statement


Find the flux of Earth's magnetic field of magnitude 5.00 10-5 T through a square loop of area 40.0 cm2 for the following:
(a) when the field is perpendicular to the plane of the loop



(b) when the field makes a 20.0° angle with the normal to the plane of the loop


Homework Equations



flux = BA cos theta
where A is the area and B is the magnetic field



The Attempt at a Solution


on the first one i just multiplied 5e-5 by .4 and i got 2.0e-5... and it was wrong and i have NO idea why

the second one i just used the answer i got previously (obviously wrong) and multiplied it by cos of 20... red x
HELP!
 
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You have to convert cm^2 to m^2 in the correct way
 


borgwal said:
You have to convert cm^2 to m^2 in the correct way

the correct way? its not directly proportional?
 


It's directly proportional, but not with the proportionality constant you think!

You seem to think that 40 cm^2 equals 0.4 m^2. That's not true!
 
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