How Does Friction Affect a Rotating Disk on an Inclined Plane?

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Homework Help Overview

The discussion revolves around the effects of friction on a rotating disk positioned on an inclined plane, particularly focusing on the direction of the frictional force when the disk is subjected to an impulsive force that causes it to move up or down the incline.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the direction of the frictional force acting on the disk during its ascent and descent. They express confusion regarding the relationship between friction and angular momentum. Other participants question the distinction between static and kinetic friction and explore the role of torque in the system.

Discussion Status

Participants are actively engaging with the concepts of friction and torque, with some providing clarifications about the nature of static versus kinetic friction. There is an ongoing exploration of how these forces interact with the motion of the disk, but no consensus has been reached on the specific mechanics involved.

Contextual Notes

There appears to be some confusion regarding the definitions and effects of static and kinetic friction, as well as the conditions under which torque is applied to the rotating disk. The discussion is framed within the constraints of a homework problem, which may limit the information available to participants.

mmainak
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Actually I am a bit confused with the direction of the frictional force acting on a rotating disk on an inclined plane.

I need to find the direction of frictional force on the rotating disk both the cases when it is going up and coming down under the action of an impulsive force applied on it which made it climb through a distance along the inclined plane.


The Attempt at a Solution



In my knowledge, if no friction acting in between them the disk would simply rotate at the same place. When we apply friction it's free rotation is obstructed and it will move on the plane while the friction is actually acting in direction of its motion.

So for a rotating disk friction acts along the motion.
But when I check the answer of the problem it is given that while it is going up the friction will act opposite to it's motion to decrease it's angular momentum.


I need a bit clarification in this regard.
 

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The drawing you posted is misleading. Frictional force (or any other force for that matter) does not increase or decrease angular velocity. You need a torque to change the angular velocity. The net torque about the cylinder axis is out of the screen regardless of whether the cylinder is rolling up or down hill.

I think that you are confusing static friction (what you have in this case) with kinetic friction. Kinetic friction opposes the motion but static friction is in whatever direction is necessary to provide the observed acceleration.
 
Last edited:
why then rotation of the disk decreases and stops at a time while it crawls up? As you said, rotating body doesn't change the angular momentum of its own, only if some external torque applied on it .Which force is supplying this torque??
 
If you calculate the torque about the point of contact, the only force that produces a torque is the weight. If you calculate the torque about the center of the cylinder, the only force that produces a torque is static friction.

Regardless of which of the two you pick, the torque will be out of the screen and so will the angular acceleration.

If the angular velocity is also out of the screen, this means that the cylinder is rolling down hill (counterclockwise). The speed will be increasing because the angular acceleration and the angular velocity are in the same direction.

If the angular velocity is into the screen, this means that the cylinder is rolling up hill (clockwise). The speed will be decreasing because the angular acceleration and the angular velocity are in opposite directions.
 

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