This discussion focuses on applying Gauss' Law to determine the electric field around a charged metal ball with a radius of 0.6 m and a charge of 0.15 nC. The electric field inside the ball is confirmed to be zero, while the field outside the ball is derived using the formula E(r) = Q / (ε₀ * 4 * π * r²). Participants clarify that the electric field decreases with increasing distance from the center of the ball, reinforcing the understanding of electric fields in conductive materials.
PREREQUISITESStudents of physics, particularly those studying electromagnetism, as well as educators and anyone seeking to deepen their understanding of electric fields and Gauss' Law applications.
Right. You have that already done in your first post. (Just change R to r in your equation for E.)kasse said:And outside the ball? I would expext the field to decrease with increasing r, not be constant...
kasse said:Homework Statement
A metal ball with radius R = 0,6 m is charged with Q = 0.15 nC. Find the electrical field as function of the distance r from the center of the ball.
The Attempt at a Solution
Gauss law:
Q = e0*E(r)*A = e0*E(r)*4*pi*R^2
which gives
E(r) = Q / e0*4*pi*R^2
I know that inside the ball, the field will be 0. But obviously this is not a function of r...Am I on the right track?