How Does Hydrogen Sulfide Affect pH and Precipitation in a Cu-Zn Solution?

AI Thread Summary
The discussion focuses on calculating the pH of a solution containing Cu²⁺ and Zn²⁺ ions after bubbling hydrogen sulfide (H₂S) gas into it. H₂S, a weak diprotic acid, dissociates in two steps, and the first dissociation significantly influences the pH. To determine the final pH, one must calculate the concentration of sulfide ions (S²⁻) and compare it to solubility product constants (Ksp) to assess potential precipitation. Participants are encouraged to reference specific equations for calculating pH and sulfide concentration. The discussion highlights the importance of understanding dissociation equilibria in this context.
dragonlady90
Messages
3
Reaction score
0

Homework Statement


A sol'n contains Cu+2(aq) and Zn+2 ions each at a con'c of 0.1M. Hydrogen sulphide gas is bubbled up into sol'n and dissociates having an initial con'c of 0.1M. Whats the pH of the final solution? Will any precipate form?
I don't know how to start the problem. Pls help me and reply soon.

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
H2S is a weak diprotic acid. Differences between both dissociation constants are large enough to calculate each dissociation equilibrium separately. You have to check what the pH is (it i will be solely governed by the first dissociation step), use this pH value to calculate S2- concentration, and check if this concetration will be large enough for precipitation (hint: look for Kso values).

For more details see this page on the pH of polyprotic substance calculation.
 
thanks for your reply Borek,

can u tell equation of this equilibrium problem so that i can solve it further. THat would be really helpful.
Once again, thanks for your reply.
 
All equations that you need to calculate pH of the solution and S2-[/sup concentration are listed on my site.
 
Are you still having problems with this question?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top