How Does Including the Quadratic Term Affect the Newton Iteration Formula?

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Homework Statement


The Newton iteration formula is based on a Taylor series expansion of the function f(x) around an estimate of the root xn, truncated after the linear term. You are asked to derive a more accurate iteration scheme as follows: Start from the Taylor series expansion of f(x) around xn, and truncate it after the quadratic term; derive then a general iteration formula for xn+1, and explain how you would use it.

Homework Equations


Newton's method equation:
af2d6f780d8673d64e8cc328ae52631d.png


Taylor's series expansion with ε=x-x0[/B]
NumberedEquation1.gif


The Attempt at a Solution


If you truncate all the terms after the linear term, it becomes a matter of simple rearrangement to isolate xn+1.

However, when truncating after quadratic term, isolating xn+1 becomes considerably more messy. My question is whether it would be valid to try to isolate xn+1. I have considered using quadratic equation but given the tediousness of this approach I am hoping for a different method.
 
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Sounds like you need to quit dodging the work and go to it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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