How Does Lunar Gravity Affect a Man's Jump Distance Compared to Earth?

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Lunar gravity, which is one-sixth that of Earth's, significantly increases a man's jump distance, allowing him to jump approximately 18 meters compared to 3 meters on Earth. The discussion also explores a basketball player's jump to reach a hoop 3.05 meters high from a distance of 10 meters, emphasizing the need for the correct initial velocity at a 45-degree angle. Participants clarify that the trajectory and physics of the jump change under different gravitational conditions, particularly noting that the range is maximized at a 45-degree launch angle. The conversation highlights the importance of understanding projectile motion in both scenarios. Overall, the effects of gravity on jump dynamics are central to the discussion.
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Homework Statement



Hi, i have a small problem, can you guys help?
1.
A man jumps a maximum horizontal distance of 3 meters. How far can he jump on the moon, where downward acceleration is g/6?

#2
A 2 meter tall basketball player, 10 meters away from the hoop 3.05 meters high, launches a basketball at a 45 degree angle. What initial velocity must he use to get it in the hoop without touching the rim?


Homework Equations



Vx= vintial*(cos theta)
X-displacement= Vx*T
V-y final= V-initial (sin theta) + AT
X displacement= V * T


The Attempt at a Solution


For number one-
I split it in half- so now I'm trying to solve
A ball is rolled off the edge of a table and lands 1.5 meters away at 45 degrees. What is Vx,
Vy final, T, and height of the table?

So first, I use
Height= 1/2 g t^2
H= 4.9 *t^2

Since D= Vx * T,
Then T= D/vx
So H= 4.9 * D^2/vx^2
Tan 45= Vy/Vx,
Vx= Vy/tan45
D= 1.5 meters
So H= 4.9 * 2.25/ (vy/tan45)
tan45=1
H= 4.9* 2.25/vy^2

and this is where i stop.

For the second question, I was thinking of perhaps the changing it to

A ball is thrown from ground level, at a 45 degree angle, to a hoop 1.05 degrees.
After that, I have no clue

Thanks for answers!

 
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your answer and question for 1st don't match. please check.
 
well started for ques2

now you can understand that the ball must the hoop during second half of its flight.
and also that it will not complete its flight.

so think of it as when the ball reaches point 1.5 along y axis, its x distance should be 10
 
cupid.callin said:
your answer and question for 1st don't match. please check.

well, no I was just looking at it from a different perspective. Instead of a man jumping 3 feet at 45 degrees, I start from his highest point and act as if he is a ball rolling off a table and landing 1.5 meters away at 45 degrees.
 
Good that you know that range is max at 45o.

now using full flight of half flight as you did, you don't need to calculate the max height or final velocities. because they will change when jumping on moon.

Can you tell me what will remain same while jumping on Earth or moon?
 
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