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**1. A basketball will be launched of height h and will hit the hoop that has a height of H. The horizontal distance between the ball and the hoop is d. Given an initial velocity Vo write both possible launch angles in function of h, H, Vo and d**

**2.**

theta=tg^-1(Vy/Vx) (1)

Vx(t)=Vo*cos(theta) (2)

Vy(t)=Vo*sen(theta)-g*t (3)

X(t)=0+Vo*cos(theta)*t (4)

Y(t)=0+Vo*sen(theta)*t-g^2/t (5)

theta=tg^-1(Vy/Vx) (1)

Vx(t)=Vo*cos(theta) (2)

Vy(t)=Vo*sen(theta)-g*t (3)

X(t)=0+Vo*cos(theta)*t (4)

Y(t)=0+Vo*sen(theta)*t-g^2/t (5)

## The Attempt at a Solution

I'm lost in how to solve this problem. My main question is:

To find the angles i have to substitute both (2) and (3) in equation (1), but when i try to do that i have the "t" in the equation. if i try to use (4) to isolate t (1) will have theta and i can't isolate it. I'm clueless as how to procede.