How Does Magnetic Field Angle Affect Force on a Current-Carrying Loop?

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Homework Help Overview

The discussion revolves around a circular loop of wire carrying current in a magnetic field, specifically examining how the angle of the magnetic field affects the force on the loop. The problem involves understanding the relationship between the current, magnetic field, and the resulting force on the loop.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore integration over the loop to determine the force, questioning the appropriate method for calculating the force based on the geometry of the setup. There is also discussion about the implications of radial forces and how they affect the loop's motion.

Discussion Status

The discussion is ongoing, with participants offering different perspectives on how to approach the problem. Some guidance has been provided regarding the integration method and the consideration of forces acting on different segments of the loop, but no consensus has been reached on a specific solution approach.

Contextual Notes

Participants are navigating assumptions about the geometry of the magnetic field and the loop, including the angle θ and its implications for the force calculation. There is uncertainty regarding the integration limits and the physical interpretation of the forces involved.

Angie K.
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Homework Statement


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A circular loop of wire, of radius r, carries current I. It is placed in a magnetic field B whose straight lines seem to diverge from a point a distance d below the ring on its axis. (That is, the field makes an angle θ with the loop at all points, where tan(θ) = r/d.) Determine the force F on the loop. Express your answer in terms of the given quantities.

Homework Equations



F = I*L*B*sinθ

The Attempt at a Solution


Not sure how to approach this.
 
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You should probably integrate it over the whole volume since dFb = I * dsXB (cross product), then the Fb =I* ∫dsXB. In this case ds will be dv - a small volume which I assume the volume of cone will be. (not sure, but maybe lighten your solution). If you consider only ds (surface) then from a triangle ds will be r/sinθ * cosθ.
∫r cosθ/sinθ dr
 
F = L * ( I × B ). So the forces will try to expand the loop, and will pull the loop downwards. So assuming that the given value of B is at the location of the wire, Fdown = I*L*B*sinθ.

L = 2πr.

Σ(radial forces) = 0
 
Last edited:
Hesch said:
Σ(radial forces) = 0

What do you mean by that?
 
Angie K. said:
What do you mean by that?

If you look at a piece of wire with the length dL, there will be an opposite piece of wire, dL, in the loop, pulled in the opposite horizontal direction. The sum of the horizontal forces = 0. The loop as a whole will not be pulled horizontally.
 

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