How Does Magnetic Field Strength Affect Ion Trajectory in a Mass Spectrometer?

AI Thread Summary
Magnetic field strength significantly influences ion trajectory in a mass spectrometer, where ions follow a semicircular path in a uniform magnetic field. For chlorine ions with a mass of 35 amu and a charge of +1e, the required magnetic field strength B can be calculated using the formula B = mv/(qr). The user calculated B to be approximately 0.095 T but initially misinterpreted the distance d as the diameter instead of the radius. Correctly identifying the radius is crucial for accurate calculations in determining the magnetic field strength needed for ions to reach the detector.
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A mass spectrometer, sketched below, is a device used to separate different ions. Such ions with a well-defined velocity Vo enter through a slit into a region of uniform magnetic field B, where they follow a semicircular path until they strike the detector slit above the entry slit. The distance between the entry and the detector slits is d = 1.30 m.

1. [1pt]
Chlorine ions of mass 35 amu (1 amu equals 1.66x10-27 kg), carrying a charge of +1e, enter the spectrometer with initial speed of vo = 3.40E5 meters/sec. What value of B is required for these ions to hit the detector?

Answer: Last Answer: -.095 T
Incorrect, tries 4/99.

I tried: r=mv/(qB) => B= mv/(qr)

B= (5.81 x 10^-26 kg x 3.40 x 10^5 m/s) / (1.60 x 10^-19 C x 1.30 m)
B= .0950 T

where did i go wrong?
 
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If I'm picturing the situation right, d = 1.30 m is the diameter. The radius is explicitly needed in your equations.
 
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