How Does Mass and Height Affect the Angular Speed of a Rotating Bicycle Wheel?

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SUMMARY

The discussion focuses on calculating the angular speed of a bicycle wheel after a block of mass m falls a distance h. The initial approach used the conservation of energy principle, equating potential energy (mgh) to kinetic energy terms (1/2mv² + 1/2Iω²). The correct relationship to use is ω = v/r, which allows for substituting v in terms of ω. The final formula for angular speed should be derived correctly by expressing v in terms of ω and solving the energy equation accurately.

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  • Understanding of rotational dynamics and moment of inertia (I)
  • Familiarity with conservation of energy principles in physics
  • Knowledge of angular velocity and its relationship to linear velocity (ω = v/r)
  • Basic algebra for solving equations involving multiple variables
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  • Study the derivation of angular speed in rotational motion using conservation of energy
  • Learn about the moment of inertia for different shapes and its impact on rotational dynamics
  • Explore the relationship between linear and angular velocity in detail
  • Practice solving problems involving falling masses and rotating objects
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PascalPanther
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"Consider the bicycle wheel is not turning initially. A block of mass m is attached (with a massless string) to a wheel. The block is allowed to fall a distance of h. Assume that the wheel has a moment of inertia I about its rotation axis.

Find the angular speed of the wheel after the block has fallen a distance of h in terms of m,g,h, r(of the wheel) and I"

This is what I did:

U + K + W(other) = U + K
mgh + 0 + 0 = 0 + 1/2mv^2 + 1/2 I*omega^2

omega = Sqrt[(2mgh - mv^2)/I]

This is wrong... what am I doing wrong? I know I can use omega = v^2/r, but not sure where that would go...
 
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PascalPanther said:
"Consider the bicycle wheel is not turning initially. A block of mass m is attached (with a massless string) to a wheel. The block is allowed to fall a distance of h. Assume that the wheel has a moment of inertia I about its rotation axis.

Find the angular speed of the wheel after the block has fallen a distance of h in terms of m,g,h, r(of the wheel) and I"

This is what I did:

U + K + W(other) = U + K
mgh + 0 + 0 = 0 + 1/2mv^2 + 1/2 I*omega^2

omega = Sqrt[(2mgh - mv^2)/I]

This is wrong... what am I doing wrong? I know I can use omega = v^2/r, but not sure where that would go...
ω = v^2/r is not correct, but it is sort of close. When you get it right, you can replace either v or ω using the correct relationship. Since you want to solve for ω, replace the v and solve away.
 

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