How Does Momentum Affect Motion in Different Scenarios?

AI Thread Summary
Momentum plays a crucial role in determining the final velocities of objects in motion after interactions, as illustrated by the scenarios presented. In the first scenario, the conservation of momentum principle indicates that the initial momentum of the boys and the boat must equal the final momentum after the boys jump. The second scenario highlights that momentum is not conserved due to external forces, requiring the calculation of net forces to determine the time taken for Lilly to stop. The third problem integrates concepts from the first two, emphasizing the importance of understanding momentum and forces in different contexts. These discussions illustrate how momentum affects motion in various physical situations.
JRKnights014
Messages
1
Reaction score
0
i have no idea at all how to do these.
someone help please

1. On a hot summer afternoon, Keith and Nate are out fishing in their rowboat when they decide to jump into the water and go for a swim. Keith, whose mass is 65.0 kg, jumps straight off the front of the boat with a speed of 2.00 m\s relative to the boat, while Nate propels his 68.0-kg body simultaneously off the back of the boat at 4.00 m\s relative to the boat. If the 100.-kg boat is initially traveling forward at 3.00 m\s, what is its velocity after both boys jump?





2. Lilly, whose mass is 45.0 kg, is ice skating with a constant speed of 7.00 m\s when she hits a rough patch of ice with a coefficient of friction of 0.0800. How long will it take before Lilly coasts to a stop?





3. In a train yard, train cars are rolled down a long hill in order to link them up with other cars as shown. A car of mass 4000. kg starts to roll from rest at the top of the hill 5.0 m high, and inclined at an angle of 5.0o to the horizontal. The coefficient of rolling friction between the train and the track is 0.050. What velocity would the car have if it linked up with 3 identical cars sitting on flat ground at the bottom of the track? (Hint: The equation for rolling friction is just like the one for sliding friction.)
 
Physics news on Phys.org
I moved your thread to the homework section of PF where homework questions belong.

Re-read the rules of the homework section (which is especially there for you!), try to show some work, and we will help you...
 
1. Conservation of momentum, the system considered is the two boys and boat initally all moving at 3.00 m/s afterwards the boys jump of, so now the boat has some final momentum. Pi-Pf=0

2. In this case momentum is not conserved, and outside force is applied. So you want to find the net forces acted on her, from there find the accelleration, with the given intial velocity and position solve for time.

Solving these first two problems should help in figuring out the third. The third problem is just asking you to integrate the first and second questions.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top