How Does Pressure in a Sealed Container Change Over Multiple Cycles?

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The discussion focuses on calculating how pressure changes in a sealed container over multiple cycles when connected to a smaller container that vents to the atmosphere. The initial setup includes a 10-liter container at a specified pressure and a 1-liter container at atmospheric pressure. After each cycle, where the valves open and close, the pressure in the larger container decreases according to a derived formula. The formula for pressure after n cycles is expressed as (Pn - Px) = (P0 - Px) * (V1/(V1 + V2))^n, where Px is the sink pressure, P0 is the initial pressure, and Pn is the pressure after n cycles. The discussion concludes that this equation can also apply if the starting pressure is below atmospheric.
jstefanop
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Im tryng to solve an equation for how pressure changes over time in a container. It goes something like this

There is a 10 liter sealed container(V1) with x amount of initial pressure (P1), and a 1 liter container attached to it (V2) with one valve that opens between them, and then another valve that opens to atmosphere. The initial pressure in the 1 liter attachment is atmospheric (P2).

For each cycle the valve opens between the pressureised 10 liter container and the one liter at 1 atm, the pressure then equalizes in both containers. Then the inner valve is closed and the outer valve is opened on the 1 liter container and pressure is vented to atmosphere (so the 1 liter container returns to 1atm) then the outside valve is closed and the cycle continues.

I need to find out after how many cycles does the large 10 liter container reach a certain pressure above 1 atm...

I can figure out what the pressure is in the container after they equalize each time which is
P= (P1*V1 +P2*V2)/(V1+V2)

So let's say the initial pressure is of P1 is 2atm after the first cycle the pressure would be P = (2*10l +1l*1atm)/(1l+10l) = 1.91 atm

then the second cycle would be P = (1.91*10l +1l*1atm)/(1l+10l) = 1.83 atm

etc etc

so what would be the equation t describe this pressure drop over a certain number of cycles? i.e. P(c) = ?
 
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jstefanop said:
P= (P1*V1 +P2*V2)/(V1+V2)
Okay.
jstefanop said:
say the initial pressure is of P1 is 2 x atm
Now try it.
 
I'll have to accept your physics, because I don't know how to do that, but juggling your equation round and using V1, V2, and P2 as constants, I get a formula for Pn after n cycles, as

( (Pn ) -1 ) = ## (\frac {10}{11})^n ## ((P0) -1 )

Edit - added excess brackets just to make clear
 
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Or in a more general form

( Pn - Px ) = ( P0 - Px ) ##( \frac{V1}{V1 + V2})^n##

Where Px is the sink pressure, P0 is the container starting pressure and Pn is the container pressure after n cycles.

Edit - BTW this looks so nice to me, that I think your physics must be correct!
Edit2 - and it looks as if you could start with container pressure below atmospheric as well.
 
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