How Does Rainfall Affect the pH of Unbuffered and Buffered Lakes?

  • Thread starter Thread starter lananh
  • Start date Start date
  • Tags Tags
    Ph
Click For Summary
SUMMARY

The discussion focuses on calculating the pH changes in a lake due to rainfall with a pH of 4.82. The lake, with a surface area of 12.2 acres and an average depth of 9.20 ft, initially has a pH of 7.00. The participant successfully calculated the moles of H3O+ from the rain as 32 moles but encountered difficulties in determining the new pH after mixing the rainwater with the lake water. Additionally, the discussion addresses the buffering capacity of the lake, which contains 0.96 mM HCO3- and 0.28 mM H2CO3, affecting the pH calculations.

PREREQUISITES
  • Understanding of pH calculations and the pH scale
  • Knowledge of acid-base chemistry, specifically monoprotic acids
  • Familiarity with buffering systems in natural waters
  • Ability to perform mole calculations based on volume and concentration
NEXT STEPS
  • Learn how to calculate pH changes in buffered solutions
  • Study the Henderson-Hasselbalch equation for buffer systems
  • Explore the impact of acid rain on freshwater ecosystems
  • Investigate methods for measuring pH in large bodies of water
USEFUL FOR

Students and professionals in environmental science, chemistry, and ecology who are interested in the effects of acid rain on freshwater systems and pH dynamics in lakes.

lananh
Messages
3
Reaction score
0

Homework Statement


Im having issues with two parts of this problem, not sure what I'm doing wrong...

A lake with a surface area of 12.2 acres (1 acre = 4.840 103 yd2) receives 1.67 in. of rain of pH 4.82. (Assume that the acidity of the rain is due to a strong, monoprotic acid.) How many moles of H3O+ are in the rain falling on the lake? I solved that the mols are 32 H3O.

If the lake is unbuffered (assume pH = 7.00) and its average depth is 9.20 ft before the rain, calculate the pH after the rain has been thoroughly mixed with lake water. (Ignore runoff from the surrounding land.)

New pH = IM HAVING ISSUES WITH THIS ONE

Natural waters are typically buffered by dissolved carbonates. If the lake originally contains 0.96 mM HCO3- and 0.28 mM H2CO3, what is the pH of the lake water before and after the rain? (Ignore runoff).

pH = (before rain) I solved it for 6.90
pH = (after rain) IM HAVING ISSUES WITH THIS ONE

any help or guidance would be greatly appreciated.


Homework Equations


ph=pka + log (a/ha)
ph=-log[h]


The Attempt at a Solution


above
 
Physics news on Phys.org
You've calculated the moles of H3O+ in the given volume of rainwater from the pH of rainwater. Next, you just need to work backwards. You know the number of moles of H3O+ from rain. Add to this the number of moles of H3O+ in the lake (pH=7), to get the total number of moles of H3O+. With this number and the final volume of the lake, you can calculate the final (unbuffered) pH.
 

Similar threads

Replies
3
Views
4K
Replies
12
Views
12K
  • · Replies 9 ·
Replies
9
Views
4K